Question

5x+15y+25=
2x²y-5xy²=
-8mn-12n²=
k(m+n)+c(m+n)=
m²kc+n²kc=

Answer 1

$5x + 15y + 25 = 5(x + 3y + 5)$

$2 {x}^{2} y - 5x {y}^{2} = xy(2 x- 5y)$

$- 8mn - 12 {n}^{2} = - 4n(2m + 3)$

$k(m + n) + c(m + n) = (m + n)(k + c)$

${m}^{2} kc + {n}^{2} kc = kc( {m}^{2} + {n}^{2} )$