Question

Реши уравнение: (13y+1)⋅(2y−2)=(26y−3)(y+1) .

Ответ:
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дам 20

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дам 20

Answer 1

1÷47

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Answer 2

Ответ:$y=\frac{25-\sqrt{599} }{26}$  .$y=\frac{25+\sqrt{599} }{26}$

Объяснение:

(13y+1)*(2y-2)=26y-3

$26y^{2} -26y+2y-2=26y-3$

$26y^{2} -24y-2=26y-3$

$26y^{2} -24y-2-26y+3=0$

$26y^{2} -50y+1=0$

$y=\frac{-(-50)+-\sqrt{(-50)^{2}-4*26*1 } }{2*26}$

$y=\frac{50+-\sqrt{2500-104} }{52}$

$y=\frac{50+-\sqrt{2396} }{52}$

$y=\frac{50+2\sqrt{599} }{52}$

$y=\frac{50-2\sqrt{599} }{52}$

$y=\frac{25+\sqrt{599} }{26}$

$y=\frac{25-\sqrt{599} }{26}$