Question

решить уравнение. sin^2x-cos^2x=1/2

Answer 1

$sin^2x-cos^2x= frac{1}{2};$
$-cos2x= frac{1}{2};$
$cos2x= -frac{1}{2};$
$2x=б( pi - frac{ pi }{3})+2 pi n,n in Z;$
$2x= бfrac{2 pi }{3}+2 pi n,n in Z;$
$x= бfrac{pi }{3}+ pi n,n in Z$