Question

Разлажите множителели
14)25/64b<2-1/81
15)2,56x<2-225/361
16)81/100-0,04c>2
ПАЖАЛУУСТА ПОМАГИТЕЕ СРОЧНОО ЗАВТРА НУЖНААА ПЖЖЖ ДАЮ 45 БАЛОВ

Answer 1

(5/8b-1/9)*(5/8b+1/9)

(1,6x-15/19)*(1,6x+15/19)

(9/10-0,2c)*(9/10+0,2c)

Answer 2

Ответ:

Объяснение:

$\displaystyle\\\frac{25}{64b^2}-\frac{1}{81} =\bigg(\frac{5}{8b}\bigg)^2- \bigg(\frac{1}{9}\bigg)^2=\bigg(\frac{5}{8b}-\frac{1}{9}\bigg) \bigg(\frac{5}{8b}+\frac{1}{9}\bigg)\\\\\\2.56x^2-\frac{225}{361} =(1.6x)^2-  \bigg(\frac{15}{19} \bigg)^2=\bigg(1.6-\frac{15}{19}\bigg)\bigg(1.6+\frac{15}{19}\bigg)\\\\\\\frac{81}{100}-0.04c^2=\bigg(\frac{9}{10} \bigg)^2-(0.2c)^2=(0.9-0.2c)(0.9+0.2c)$