Question

Квадратное с модулем?

Answer 1

$|8x-x^2-17|+|2x-32|=x^2-10x+49\\-x^2+8x-17=0\Leftrightarrow x^2-8x+17=0\\D_1=16-17<0\Rightarrow x\in \varnothing \Rightarrow \\\Rightarrow x^2-8x+17+2|x-16|=x^2-10x+49\Leftrightarrow \\\Leftrightarrow 2|x-16|=-2x+32\Leftrightarrow |x-16|=-(x-16)\Rightarrow \\\Rightarrow x\leq 16$

Answer 2

Ответ:

Объяснение:

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