Question

Помогите, 20 баллов, задание на фото

Answer 1

#1

1) 0.1*$\sqrt{900}$-1/4*$\sqrt{64}$=0.1*30-0.25*8=3-2=1

2) $\sqrt{25}$*$\sqrt{0.04}$+$\sqrt{3^3+22}$=5*0.2+7=8

3) $4\sqrt{0.49} -\sqrt{8^2+15^2} =4*0.7-\sqrt{289} =2.8-17=-14.2$

#2

1) $(\sqrt{7}) ^2$-$\sqrt{1.21}$=7-1.1=5.9

2) $(4\sqrt{3} )^2-(3\sqrt{5} )^2=16*3-9*5=48-45=3$

3) 32*(-1/2$\sqrt{11}$)^2=32*1/4*11=8*11=88

Answer 2

Ответ:

$1.1) 0,1\sqrt{900} - \frac{1}{4}\sqrt{64} = \frac{30}{10} - \frac{8}{4} = 3 - 2 = 1$

$1.2) \sqrt{25}*\sqrt{0,04}+\sqrt{3^3+22} = 5*0,2+\sqrt{27+22} = 1+\sqrt{49} = 8$

$1.3) 4\sqrt{0,49} - \sqrt{8^2+15^2} = 4*0,7 - \sqrt{64+225} = 2,8 - \sqrt{289} = 2,8 - 17 = -14,2$

$1.4) \sqrt{2\frac{2}{49}} +\sqrt{2\frac{7}{9}} - 0,03\sqrt{40000} = \sqrt{\frac{100}{49}}   +\sqrt{\frac{25}{9}} - 0,03*200 = \frac{10}{7} + \frac{5}{3} - 6 =\\\\ \frac{30 + 15}{21} - 6 = \frac{45}{21} - 6 = 2\frac{3}{21} - 6 = 2\frac{1}{7} - 6 = -4\frac{1}{7}$

$2.1) (\sqrt{7})^2 - \sqrt{1,21} = 7 - 1,1 = 5,9$

$2.2) (4\sqrt{3})^2 - (3\sqrt{5})^2 = 16*3 - 9*5 = 48 - 45 = 3$