Question

Решите уравнение
1) 5х(8-х)=х(х-8)
2) х^2(х-9)=2(9-х)

Answer 1

Ответ:

1) х1 =0 , х2=8

2)х1 =-1 , х2=9

Answer 2

$1)\; \; 5x(8-x)=x(x-8)\\\\5x(8-x)-x(x-8)=0\\\\x(8-x)(5+1)=0\; \; ,\; \; 6x\, (8-x)=0\\\\\underline {x_1=0\; ,\; x_2=8}\\\\\\2)\; \; x^2(x-9)=2(9-x)\\\\x^2(x-9)-2(9-x)=0\\\\(x-9)(x^2+2)=0\\\\(x^2+2)>0\; \; ,\; \; x-9=0\; \; \to \; \; \underline {x=9}$