Question

$\frac{ {2x}^{2} }{ {x}^{2} - 4 } - \frac{2 x}{ x + 2}$
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Answer 1

Пошаговое объяснение:

$\frac{2x {}^{2} }{x {}^{2} - 4} - \frac{2x}{x + 2} \\ \frac{2x {}^{2} }{(x - 2)(x + 2)} - \frac{2x}{x + 2} \\ \frac{2x {}^{2 } - 2x \times (x - 2) }{(x - 2)(x + 2)} \\ \frac{2x {}^{2} - 2x {}^{2} + 4x }{x {}^{2} - 4 } \\ \frac{4x}{x {}^{2} - 4}$