Question

(x^2 -x-56)*(x-3)
____________
x^2 +5x+6


$\frac{1}{4}^x^-^1^5 =\frac{1}{64}$
$\frac{1}{2}^6^-^2^x =4$

Answer 1

1.

$\frac{1}{4}^{x-15}=\frac{1}{64}$

$\frac{1}{4}^{x-15}=\frac{1}{4}^3\\x-15=3\\x=18$

2.

$\frac{1}{2}^{6-2x}=4\\\frac{1}{2}^{6-2x}=\frac{1}{2}^{-2}\\6-2x=-2\\-2x=-8\\x=4$