Question

Помогите матешу пж 349 номер даю 40 балов (да я укр)

Answer 1

$349.\\1)\;9\frac35\cdot\frac{10}{21}=\frac{9\cdot5+3}{5}\cdot\frac{10}{21}=\frac{45+3}5\cdot\frac{10}{21}=\frac{48}5\cdot\frac{10}{21}=\frac{16}1\cdot\frac27=\frac{32}7=4\frac47\\\\2)\;3\frac{11}{12}\cdot\frac9{94}=\frac{3\cdot12+11}{12}\cdot\frac9{94}=\frac{36+11}{12}\cdot\frac9{94}=\frac{47}{12}\cdot\frac9{94}=\frac14\cdot\frac32=\frac38$

$3)\;1\frac57\cdot6\frac18=\frac{1\cdot7+5}7\cdot\frac{6\cdot8+1}8=\frac{7+5}7\cdot\frac{48+1}8=\frac{12}7\cdot\frac{49}8=\frac31\cdot\frac72=\frac{21}2=10\frac12\\\\4)\;3\frac59\cdot5\frac14=\frac{3\cdot9+5}9\cdot\frac{5\cdot4+1}4=\frac{27+5}9\cdot\frac{20+1}4=\frac{32}9\cdot\frac{21}4=\frac83\cdot\frac71=\frac{56}3=18\frac23$

$5)\;1\frac{13}{15}\cdot\frac58\cdot2\frac27=\frac{1\cdot15+13}{15}\cdot\frac58\cdot\frac{2\cdot7+2}{7}=\frac{15+13}{15}\cdot\frac58\cdot\frac{14+2}7=\frac{28}{15}\cdot\frac58\cdot\frac{16}7=\frac43\cdot\frac11\cdot\frac21=\frac83=2\frac23\\\\6)\;2\frac14\cdot\frac{16}{27}\cdot4\frac13=\frac{2\cdot4+1}4\cdot\frac{16}{27}\cdot\frac{4\cdot3+1}3=\frac{8+1}4\cdot\frac{16}{27}\cdot\frac{12+1}3=\frac94\cdot\frac{16}{27}\cdot\frac{13}3=\frac11\cdot\frac43\cdot\frac{13}3=\frac{52}9=5\frac79$