Question

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Заранее спасибо

Answer 1

$\frac{(2+1)(2^2+1)(2^4+1)***(2^{32}+1)}{2^{64}-1}=\frac{(2+1)(2^2+1)(2^4+1)***(2^{32}+1)}{(2^{32}-1)(2^{32}+1)}=\\=\frac{(2+1)(2^2+1)(2^4+1)***(2^{32}+1)}{(2^{16}-1)(2^{16}+1)(2^{32}+1)}=\frac{(2+1)(2^2+1)(2^4+1)***(2^{32}+1)}{(2-1)(2+1)(2^2+1)(2^4+1)(2^{8}+1)(2^{16}+1)(2^{32}+1)}=1$