Question

помогите решить пределы​

Answer 1

$1) \lim_{x \to5}\frac{x^2-6x+5}{x^2-25} = \lim_{x \to5}\frac{(x-1)(x-5)}{(x-5)(x+5)}= \lim_{x \to5} \frac{x-1}{x+5} =\frac{2}{5}\\2) \lim_{x \to-1} \frac{x^3+x+2}{x^3+1}= \lim_{x \to-1}\frac{3x^2+1}{3x^2}=\frac{4}{3}\\3) \lim_{x \to1} \frac{x^3-x^2+3x-3}{2x^3-2x^2+x-1}= \lim_{x \to1}\frac{(x-1)(x^2+3)}{(x-1)(2x^2+1)}= \lim_{x \to1} \frac{x^2+3}{2x^2+1}=\frac{4}{3}$