Question

Ооочень нужна ваша помощь​

Answer 1

$\displaystyle \bigg( \frac{2y + 1}{ {y}^{2} + 6y + 9} - \frac{y - 2}{ {y}^{2} + 3y} \bigg) \div \frac{ {y}^{2} + 6}{ {y}^{3} - 9y} = \frac{y - 3}{y + 3} \\ \bigg( \frac{2y + 1}{(y + 3)^{2} } - \frac{y - 2}{y(y + 3)} \bigg) \div \frac{ {y}^{2} + 6}{y( {y}^{2} - 9)} = \frac{y - 3}{y + 3} \\ \frac{y(2y + 1) - (y + 3)(y - 2)}{y(y + 3)^{2} } \div \frac{ {y}^{2} + 6 }{y( {y}^{2} - 9)} = \frac{y - 3}{y + 3} \\ \frac{2 {y}^{2} + y - {y}^{2} + 2y - 3y + 6 }{y(y + 3)^{2} } \div \frac{ {y}^{2} + 6}{y( {y}^{2} - 9)} = \frac{y - 3}{y + 3} \\ \frac{( {y}^{2} + 6)}{y(y + 3)^{2} } \times \frac{y( {y}^{2} - 9 )}{( {y}^{2} + 6)} = \frac{y - 3}{y + 3} \\ \frac{(y - 3)(y + 3)}{(y + 3)(y + 3)} = \frac{y - 3}{y + 3} \\ \frac{y - 3}{y + 3} = \frac{y - 3}{y + 3}$

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