Question

Вычеслить: arctg (-√3) - arccos (-√3/2) + arcsin (-√3/2) - arccos1

Answer 1

$arctg (-sqrt{3})-arccos(-frac{sqrt{3}}{2})+arcsin (-frac{sqrt{3}}{2})-arccos 1=\\-frac{pi}{3}-(pi-frac{pi}{6})-frac{pi}{3}-0=-frac{4pi+5*pi}{6}=-frac{3*pi}{2}$