Question

Помогите срочно ......... ​

Answer 1

Объяснение:

$\frac{3^2\cdot 4^3\cdot 12^2}{9^2\cdot 6^3}=\frac{3^2\cdot (2^2)^3\cdot (3\cdot 2^2)^2}{(3^2)^2\cdot (2\cdot 3)^3}=\frac{3^2\cdot 2^6\cdot 3^2\cdot 2^4}{3^4\cdot 2^3\cdot 3^3}=\frac{3^4\cdot 2^{10}}{3^7\cdot 2^3}=\frac{2^7}{3^3}=\frac{128}{27}=4\frac{20}{27}$

$\frac{5^2\cdot 6^4\cdot 12^2}{15^2\cdot 9^3}=\frac{5^2\cdot (2\cdot 3)^4\cdot (3\cdot 2^2)^2}{(3\cdot 5)^2\cdot (3^2)^3}=\frac{5^2\cdot 2^4\cdot 3^4\cdot 3^2\cdot 2^4}{3^2\cdot 5^2\cdot 3^6}=\frac{5^2\cdot 2^8\cdot 3^6}{5^2\cdot 3^8}=\frac{2^8}{3^2}=\frac{256}{9}=28\frac{4}{9}$