Question

4X(3x+3)-3(x-5)-9(x+3)=0

Answer 1

$4x(3x + 3) - 3(x - 5) - 9(x + 3) = 0 \\ 12 {x}^{2} + 12x - 3x + 15 - 9x - 27 = 0 \\ 12x ^{2} + 0 - 12 = 0 \\ 12 {x}^{2} - 12 = 0 \\ {x}^{2} - 1 = 0 \\ {x}^{2} = 1 \\ x = + - 1 \\ x1 = - 1 \\ x2 = 1$

Answer 2

Объяснение:

$4x \times (3x + 3) - 3(x - 5) - 9 \times (x + 3) = 0 \\ \\ 12x {}^{2} + 12x - 3x + 15 - 9x - 27 = 0 \\ \\ 12x {}^{2} - 12 = 0 \\ \\ x {}^{2} - 1 = 0 \\ \\ x {}^{2} = 1 \\ \\ x1 = - 1 \\ \\ x2 = 1$

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