Question

10, если можно. Заранее спасибо

Answer 1

$(x - 2) ^{3} = (x - 5) {}^{2} (x + 4) \\ x {}^{3} - 6x {}^{2} + 12x - 8 = (x {}^{2} - 10x + 25)(x + 4) \\ x {}^{3} - 6x {}^{2} + 12x - 8 =x {}^{3} + 4x {}^{2} - 10x {}^{2} - 40x + 25x + 100 \\ x {}^{3} - 6x {}^{2} + 12x - 8 =x {}^{3} - 6x {}^{2} - 15x + 100 \\ x {}^{3} - x {}^{3}- 6x {}^{2}+ 6x {}^{2}+12x + 15x = 100 + 8 \\ 27x = 108 | \div 27 \\ x = 4$