Question

(1×1/2)×(1+1/3)×(1+1/4)×.......×(1+1/15) =​

Answer 1

$(1+\frac{1}{2})\cdot (1+\frac{1}{3})\cdot (1+\frac{1}{4})\cdot ...\cdot (1+\frac{1}{13})\cdot (1+\frac{1}{14})\cdot (1+\frac{1}{15})=\\\\=\frac{3}{2}\cdot \frac{4}{3}\cdot \frac{5}{4}\cdot ...\cdot \frac{14}{13}\cdot \frac{15}{14}\cdot \frac{16}{15}=\frac{16}{2}=8$

Answer 2

(1/2)*(4/3)*(5/4*(6/5)*(7/6)...(16/15)=(1/2)*((4*5*6*7*...16)/(3*4*5*6*...14*15)=

(1/2)*(16/3)=8/3=2целые 2/3