Question

Помогите решить 1 номер

Answer 1

2sin(π/3 - 2x) = 1

sin(π/3 - 2x) = 0,5

π/3 - 2x = π/6 + 2πk

π/3 - 2x = 5π/6 + 2πk

-2x = -π/6 + 2πk

-2x = π/2 + 2πk

x = π/12 - πk

x = -π/4 - πk

x = π/12 + πk

x = -π/4 + πk

Ответ : π/12 + πk, -π/4 + πk ; k € Z