Question

2. Задание
y’=(arctg sqrt1-x^2)’

Answer 1

Ответ:

Пошаговое объяснение:

y' = (arctg√(1-x²))' = 1/(1 + (1-x²)) * (√(1-x²))' = -1/(2 - x²) * 2x/(2√(1-x²)) =

= -x/((1-x²)(2-x²))

Answer 2

y' = (arctg√(1-x²))' = 1/(1 + (√(1-x²))²) * (√(1-x²))' = -2x/(2 - x²)2√(1-x²) =  

= -x/((√1-x²)(2-x²))