Question

Возведите в квадрат:
1) (Х + 5)^2
2) (3у - х)^2
3) (4-х)^2
4) (6х + 2)^2

Answer 1

1)(x+5)²=(x)²+2*x*5+5²=x²+10x+25

2)(3y-x)²=(3y)²-2*3y*x+(x)²=9y²-6xy+x²=x²-6xy+9y²

3)(4-x)²=4²-2*4*x+(x)²=16-8x+x²=x²-8x+16

4)(6x+2)²=(6x)²+2*6x*2+2²=36x²+24x+4