Question

Очень, очень срочно !!! Помогите!!!

Answer 1

$1)\frac{t^{2}-4t+16 }{16t^{2}-1 }*\frac{4t^{2}+t }{t^{3}+64 }=\frac{t^{2}-4t+16}{(4t-1)(4t+1)}*\frac{t(4t+1)}{(t+4)(t^{2}-4t+16)}=\frac{t}{(4t-1)(t+4)}\\\\2)\frac{t}{(4t-1)(t+4)}-\frac{t+4}{4t^{2}-t } =\frac{t}{(4t-1)(t+4)}-\frac{t+4}{t(4t-1)}=\frac{t^{2}-(t+4)^{2}}{t(4t-1)(t+4)}=\frac{t^{2}-t^{2}-8t-16}{t(4t-1)(t+4)} =\frac{-8(t+2)}{t(4t-1)(t+4)}$

$3)\frac{-8(t+2)}{t(4t-1)(t+4)}:\frac{4}{t^{2}+4t }=\frac{-8(t+2)}{t(4t-1)(t+4)}*\frac{t(t+4)}{4}=\frac{-2(t+2)}{4t-1} \\\\4)\frac{-2(t+2)}{4t-1}-\frac{20t+13}{4-16t}=\frac{-2(t+2)}{4t-1}-\frac{20t+13}{4(1-4t)}=\frac{-2t-4}{4t-1}+\frac{20t+13}{4(4t-1)}=\frac{-8t-16+20t+13}{4(4t-1)} =\frac{12t-3}{4(4t-1)}=\frac{3(4t-1)}{4(4t-1)}=\frac{3}{4}=0,75$

$Otvet:\frac{3}{4}$