Question

y=kx+b A(7;3),B(-2;4). Решите

Answer 1

$k = \frac{y2 - y1}{x2 - x1} = \frac{4 - 3}{ - 2 - 7} = - \frac{1}{9} \\k = \frac{y - y1}{x - x1} = \frac{y - 3}{x - 7} = - \frac{1}{9} \\ 9y - 27 = - x + 7 \\ 9y = - x + 7 + 27 \\ 9y = - x + 34 \\ y = - \frac{1}{9} x + \frac{34}{9} \\ y = - \frac{1}{9} x + 3 \frac{7}{9}$