Question

помогите пожалуйста!​

Answer 1

$\begin{cases} x-y=5\frac{1}{3}\\x+y=6\frac{2}{3}\end{cases}\\\\\begin{cases} x-y= \frac{16}{3}\ \ /*3 \\x+y= \frac{20}{3}\ \ / *3\end{cases}\\\\\begin{cases} 3x-3y=16 \\3x+3y=20\end{cases}\\+-------\\6x=36\ \ /:6\\x=6$

$x+y=6\frac{2}{3}\\6+y=6\frac{2}{3}\\\\y=6\frac{2}{3}-6\\\\x=\frac{2}{3}\\\\\\\begin{cases}x=6\\y= \frac{2}{3}\end{cases}$