Question

Помогите с номером 1,2 Вариант 6

Answer 1

$1)\frac{lg2+lg3}{lg3,6+1}=\frac{lg(2*3)}{lg3,6+lg10}=\frac{lg6}{lg36}=\frac{lg6}{lg6^{2} }=\frac{lg6}{2lg6}=\frac{1}{2}=0,5\\\\2)\frac{a^{\frac{7}{3}}-a^{\frac{1}{3}}}{a^{\frac{7}{3}}+a^{\frac{4}{3}}}=\frac{a^{\frac{1}{3} }(a^{2}-1)}{a^{\frac{4}{3}}(a+1) }=\frac{(a-1)(a+1)}{a(a+1)}=\frac{a-1}{a}$