Question

решите пж.
\—(°.°)—/​

Answer 1

$\frac{1}{3} x + 12 = x - \frac{1}{6} x + 3$

$\frac{1}{3} x + \frac{1}{6} x - x = 3 - 12$

$\frac{1}{2} - x = - 9$

$- \frac{1}{2} x = - 9$

$x = 9 \div \frac{1}{2}$

$x = 18$

Ответ :

$18$

Answer 2

Решение:

$\frac{1}{3}x + 12 = x - \frac{1}{6}x + 3$

$\frac{1}{3} x + 12 = x(1 - \frac{1}{6} ) + 3$

$\frac{1}{3} x + 12 = \frac{5}{6}x +3$

$12 - 3 = \frac{5}{6}x - \frac{1}{3} x$

$9 = \frac{1}{2}x$

$x = 9 \div \frac{1}{2}$

$x = 18$

Ответ: 18