Question

(х+5)(х+2)-3(4х-3)=(х-5)^2

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Answer 1

(х+5)(х+2)-3(4х-3)=(х-5)^2

${ x}^{2} + 2x + 5x + 10 - 12x + 9 = { x}^{2} - 10x + 25$

${x}^{2} - 5x + 19 = {x}^{2} - 10x + 25$

${x}^{2} - 5x + 19 - {x}^{2} + 10x - 25 = 0$

5х-6=0

$5x = 6$

$x = \frac{6}{5}$

$x = 1 \frac{1}{5}$

Ответ: $x = 1 \frac{1}{5}$ или 1,2.