Предмет: Геометрия, автор: studentkaupk

диагональ осевого сечения цилиндра а= 26см, высота h=24 см. вычислите площадь основания цилиндра

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Автор ответа: Матов

Тогда диаметр основания равен
$D=sqrt{26^2-24^2}=10\ D=2r\ r=5\ S=5^2*pi=25pi$
или 25*3.14=78.5 см кв

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