Question

Сократите дробь

28^2n+1
__________
2^n+2 * 7^n+1

20 баллов)))

Answer 1

$\frac{28^{2n+1} }{2^{n+2}*7^{n+1}}=\frac{(4*7)^{2n+1} }{2^{n+2}*7^{n+1}}=\frac{(2^{2})^{2n+1}*7^{2n+1}}{2^{n+2}*7^{n+1}}=\frac{2^{4n+2}*7^{2n+1}}{2^{n+2}*7^{n+1}} =2^{4n+2-n-2}*7^{2n+1-n-1}=2^{3n}*7^{n}=8^{n}*7^{n}=56^{n}$