Question

решите уравнение $(4x+3)^{2} -(4x-1)*(1+4x)=65$

Answer 1

$(4x+3)^2-(4x-1)(4x+1)=65\\\\(16x^2+24x+9)-(16x^2-1)=65\\\\24x+9+1=65\\\\24x=55\\\\x=\frac{55}{24}\\\\x=2\frac{7}{24}$