Question

Помогите решить
sin x = -0,5 * √2

Answer 1

sinx = -√2/2;

x = (-1)ⁿarcsin(-√2/2) + πn, n∈Z;

x = (-1)ⁿ⁺¹π/4 + πn, n∈Z.

Ответ: (-1)ⁿ⁺¹π/4 + πn, n∈Z.

Answer 2

$sinx=-0,5\cdot \sqrt2\\\\x=(-1)^{n}\cdot arcsin(-\frac{\sqrt2}{2})+\pi n,\; n\in Z\\\\x=(-1)^{n}\cdot (-\frac{\pi}{4})+\pi n,\; n\in Z\\\\x=(-1)^{n+1}\cdot \frac{\pi}{4}+\pi n,\; n\in Z$