Question

Помогите пожалуйста ​

Answer 1

2•3-3/3+m=0
6-1+m=0
m=-5 => C)

Answer 2

$2\sqrt3\, ctgx-\sqrt3\, tgx+m=0\; \; ,\; \; x=\frac{\pi}{6}\\\\2\sqrt3\cdot ctg\frac{\pi}{6}-\sqrt3\cdot tg\frac{\pi}{6}+m=0\\\\2\sqrt3\cdot \sqrt3-\sqrt3\cdot \frac{\sqrt3}{3}+m=0\\\\2\cdot 3-\frac{3}{3}+m=0\\\\6-1+m=0\\\\m=-5$