Question

Решите уравнение
$left { {{(x-y)^{2}-x+y=o} atop { x^{2}y^{2}-xy-2=o}} right.$

Answer 1

$left { {{(x-y)^2-x+y=0} atop {y^2-xy-2=0}} right.\ \ x^2-2xy+y^2-x+y=y^2-xy-2\ x^2-xy-x+y=-2\ x(x-y)-(x-y)=-2\ (x-y)(x-1)=-2\ y=frac{-2}{x-1}-x\ (frac{-2}{x-1}-x)^2-x*(frac{-2}{x-1}-x)-2=0\ x=-1\ y=-2$