Question

срочно, помогите!!! Серкз дискриминант. Даю 26 баллов!)​

Answer 1

$\frac{x^{2}-4x }{8}*120+\frac{x-3}{5}*120=\frac{1-x}{6}*120\\\\15(x^{2}-4x)}+ 24(x-3)=20(1-x)\\\\15x^{2}-60x+24x-72-20+20x=0\\\\15x^{2}-16x-92=0\\\\\frac{D}{4}=(-8)^{2}-15*(-92)=64+1380=1444=38^{2}\\\\x_{1} =\frac{8+38}{15}=\frac{46}{15}=3\frac{1}{15}\\\\x_{2}=\frac{8-38}{15}=\frac{-30}{15}=-2$