Предмет: Физика, автор: tori4155

яка силу струму слід прикласти до опору в 25 Ом щоб одержати у ньому напругу 650 В

Ответы

Автор ответа: nlyga1111

1

Згідно закону Ома $I=\frac{U}{R}=\frac{650}{25}= 26 A$

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