Question

$\frac{x}{x-5} +\frac{3x+15}{x^{2} -25} =0$

Answer 1

x≠-5, x≠5

$\frac{x}{x-5} +\frac{3x+15}{x^{2} -25} =0\\\\\frac{x(x+5)}{(x-5)(x+5)} +\frac{3x+15}{x^{2} -25} =0\\\\\frac{x(x+5) +3x+15}{x^{2} -25} =0\\\\x(x+5) +3x+15 =0\\\\x(x+5) +3(x+5) =0\\\\(x+5)(x+3)=0\\\\x+5=0\ \ \ \ \ x+3=0\\\\x=-5\ \ \ \ \ \ \ \ x=-3$

Ответ: -3