Question

(2m+3)^2-(3-2m)^2=

(2b+3)^2-(5+b)^2=

(5a+4)^2-25a^2=

СРОЧНО ПОЖАЛУСТА

Answer 1

$(2m+3)^2-(3-2m)^2=\\=4m^2+12m+9-4m^2+12m-9=\\=24m$

$(2b+3)^2-(5+b)^2=\\=4b^2+12b+9-b^2-10b-25=\\=3b^2+2b-16=\\=(b-2)(3b+8)$

$(5a+4)^2-25a^2=\\=25a^2+40a+16-25a^2=\\=40a+16=\\=8(5a+2)$