Question

Решите уравнение

(6-х)³-х²(16-х)=2х²+116

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Answer 1

$\tt (6-x)^3-x^2(16-x)=2x^2+116\\216-108x+18x^2-x^3-16x^2+x^3=2x^2+116\\2x^2-108x +216=2x^2+116\\2x^2-2x^2-108x=116-216\\-108x=-100\\x=\cfrac{-100}{-108}= \cfrac{25}{27}$