Question

6 класс. Самостоятельная. СРОЧНО!!

Answer 1

$1.\\a)\;-4,1-(-1,6+2,32)=-4,1-0,72=-4,82\\b)\;-1\frac57+\left(-2\frac13-1\frac27\right)=-1\frac{15}{21}-2\frac7{21}-1\frac6{21}=-4\frac{28}{21}=-5\frac7{21}=-5\frac13\\c)\;(4,6-5,9)+1\frac13-\left(2\frac25-\frac23\right)=-1,3+1\frac13-\left(2\frac6{15}-\frac{10}{15}\right)=-1\frac3{10}+1\frac13-1\frac{11}{15}=\\=-1\frac9{30}+1\frac{10}{30}-1\frac{22}{30}=-1\frac{21}{30}=-1\frac{7}{10}$

$2.\\a)\;-(-b+1,2)+3,2=b-1,2+3,2=b+2\\b)\;(-2,8+n)-n=-2,8+n-n=-2,8\\c)\;(4,3-y)-(5,8+y)=4,3-y-5,8-y=-1,5-2y$

$3.\\a)\;4,5-(m+2,8)=4,5-m-2,8=1,7-m=1,7-(-2,2)=1,7+2,2=3,9\\b)\;-n+(3,8-n)+4,3=-n+3,8-n+4,3=8,1-2n=8,1-2\cdot0,8=8,1-1,6=6,5$

$4.\;1\frac23-(y+2)=-2\frac13\\y+2=1\frac23+2\frac13\\y+2=4\y=4-2\\y=2\\\Pi POBEPKA:\;1\frac23-(2+2)=1\frac23-4=-2\frac13\\\\5.\;b+b+a-(b-a)=b+b+a-b+a=b+2a$

Answer 2

№1.

а) - 4,1-(-1,6+2,32)= -4,1+1,6-2,32=-4,82

б)

$- 1\frac{5}{7} + ( - 2 \frac{1}{3} - 1 \frac{2}{7}) = \\ - 1 \frac{5}{7} - 2 \frac{1}{3} - 1 \frac{2}{7} = - 5 \frac{1}{3}$

в)

$(4.6 - 5.9) + 1\frac{1}{3} - (2 \frac{2}{5} - \frac{2}{3} ) = \\ - 1.3 + 1 \frac{1}{3} - 2 \frac{2}{5} + \frac{2}{3} = \\ \frac{23}{5} - \frac{59}{10} + \frac{4}{3} - \frac{26}{15} = - 1 \frac{7}{10}$

№2

a)-(-b+1,2)+3,2=b-1,2+3,2=b+2

b)(-2.8+n)-n= - 2,8+n-n= -2,8

c)(4,3-y)-(5.8+y)=4,3-y-5,8-y= -1,5-2y

№3

а)4,5-(m+2,8)=4,5-m-2,8=1,7-m

Если m=-2,2,то 1,7-(-2,2)=3,9

б) -n+(3.8-n)+4,3=-n+3.8-n+4,3=8,1-2n
Если n=0,8,то 8,1-1,6=6,5

№4

$1 \frac{2}{3} - (y + 2) = - 2 \frac{1}{3} \\ 1 \frac{2}{3} - y - 2 = - 2\frac{1}{3} \\ - y = - 2 \frac{1}{3} - 1 \frac{2}{3} + 2 \\ - y = - \frac{7}{3} + \frac{1}{3} \\ y = 2$

Проверка: 1 2/3-(2+2)=-2 1/3

1 2/3-4= - 2 1/3

-2 1/3=-2 1/3

№5

b+b+a-(b-a)=b+2a

2b+a-b+a=b+2a

b+2a=b+2a