Question

Заранее спасибо!)
Только задания с уравнениями из каждой из частей(задание 2)

Answer 1

Задание 2.1

(7y - 2)² + 25y = 1 + 49y²

49y² - 28y + 4 + 25y - 1 - 49y² = 0

-3y + 3 = 0

-3y = -3

y = 1

Задание 2.2

(4x + 3)² - 10x = 16x² + 1

16x² + 24x + 9 - 10x - 16x² - 1 = 0

14x + 8 = 0

14x = -8

x = -⁸/₁₄ = -⁴/₇

Задание 2.3

(x + 3)(x + 7) - (x + 4)² = 0

x² + 7x + 3x + 21 - (x² + 8x + 16) = 0

x² + 10x + 21 - x² - 8x - 16 = 0

2x + 5 = 0

2x = -5

x = -⁵/₂

Задание 2.4

(x - 3)² - (x - 5)(x + 3) = 0

x² - 6x + 9 - (x² - 5x + 3x - 15) = 0

x² - 6x + 9 - x² + 5x - 3x + 15 = 0

-4x + 24 = 0

-4x = -24

x = 6

Answer 2

$(7y - 2)^{2} + 25y = 1 + 49y \\ 49y - 28y + 4 + 25y - 1 - 49y = 0 \\ - 3y + 3 = 0 \\ 3y = - 3 \\ y = \frac{ - 3}{3} \\ y = - 1$
$(4x + 3)^{2} - 10x = 16 {x}^{2} + 1 \\ 16 {x}^{2} + 24x + 9 - 10x - 16 {x}^{2} - 1 = 0 \\ 14x + 8 = 0 \\ 14x = - 8 \\ x = \frac{ - 8}{14} \\ x = \frac - {4}{7}$
$(x + 3)(x + 7) - (x + 4)^{2} = 0 \\ {x}^{2} + 7x + 3x + 21 - ( {x}^{2} + 8x + 16) = 0 \\ {x}^{2} + 10x + 21 - {x}^{2} - 8x - 16 = 0 \\ 2x + 5 = 0 \\ 2x = - 5 \\ x = \frac{ - 5}{2} \\ x = - 2.5$