Question

y=sqrt(2x-3)/cosx/2 найти производную

Answer 1

$y=\frac{\sqrt{2x-4}}{cos\frac{x}{2}}\\\\y'=\frac{\frac{1}{2\sqrt{2x-4}}\cdot 2\cdot cos\frac{x}{2}-\sqrt{2x-4}\cdot (-sin\frac{x}{2})\cdot \frac{1}{2}}{cos&2\frac{x}{2}}=\frac{2\, cos\frac{x}{2}+(2x-4)\cdot sin\frac{x}{2}}{2\sqrt{2x-4}\cdot cos^2\frac{x}{2}}=\frac{cos\frac{x}{2}+(x-2)\cdot sin\frac{x}{2}}{\sqrt{2x-4}\cdot cos^2\frac{x}{2}}$