Question

Помогите решить уравнение пожалуйста

x²-4x+16/x³+64=2/17

Answer 1

$\frac{x^2-4x+16}{x^3+64}=\frac{2}{17}\\\\\frac{x^2-4x+16}{(x+4)(x^2-4x+16)}=\frac{2}{17}\; ,\; \; x\ne 4\; ;\; x^2-4x+16>0,\; t.k.\; D=-48<0\\\\\frac{1}{x+4}=\frac{2}{17}\\\\2x+8=17\\\\2x=9\\\\x=4,5$

Answer 2

$\frac{x^{2}-4x+16 }{x^{3} +64}=\frac{2}{17} \\\\\frac{x^{2} -4x+16}{(x+4)(x^{2}-4x+16) }=\frac{2}{17}\\\\\frac{1}{x+4}=\frac{2}{17} ,x\neq -4\\\\2(x+4)=17\\\\x+4=8,5\\\\x=4,5$