Question

помогите пожалуйста.

Answer 1

$(\frac{x}{x^2-2x+1}-\frac{1}{x-1}):\frac{5}{(x-1)^2}=\\\\(\frac{x}{(x-1)^2}-\frac{x-1}{(x-1)^2})\cdot\frac{(x-1)^2}{5}=\\\\\frac{x-x+1}{(x-1)^2}\cdot\frac{(x-1)^2}{5}=\frac{1}{5}$