Question

Даю 98 баллов, помогите алгебра!!!

Answer 1

cos√(4-|x|)=0
4-|x|>0
|x|<4
-4<x<4 ODZ
√(4-|x|)=π/2+πk
(4-|x|)=(π/2+πk)²;

|x|=4-(π/2+πk)²
4-(π/2+πk)²>0
(π/2+πk)²<4
-2<π/2+πk<2
k=0
x=4-(π/2)²=4-1,57²=
4-2,5=1,5

к=-1
х=4-(π/2-π)²=4-(-π/2)²=
4-2,5=1,5