Question

3^(x+2) 8*5^(x-1) = 5^(x+1) + 10*3^(x-1)

Answer 1

$3^{x+2}+8*5^{x-1}=5^{x+1}+10*3^{x-1}\\\\3^{x+2} -10*3^{x-1}=5^{x+1}-8*5^{x-1}\\\\3^{x-1}(3^{3} -10)=5^{x-1}(5^{2}-8)\\\\17*3^{x-1}=17*5^{x-1}\\\\3^{x-1}=5^{x-1}\\\\\frac{3^{x-1} }{5^{x-1} }=\frac{5^{x-1} }{5^{x-1} } \\\\(\frac{3}{5})^{x}=1\\\\(\frac{3}{5})^{x-1}=(\frac{3}{5})^{0}\\\\x-1=0\\\\x=1$