Question

Решить уравнение на фото

Answer 1

$\frac{4x - 4}{x} + \frac{ {x}^{2} + 4 }{x(x + 1)} = \frac{6 + x}{x + 1} \\ (4x - 4)(x + 1) + \\ {x}^{2} + 4 = x(6 + x)$
${4x}^{2} + 4x - 4x - 4 + {x}^{2} + 4 \\ = 6x + {x}^{2} \\ {5x}^{2} - 6x - {x}^{2} = 0$
${4x}^{2} - 6x = 0 \\ 2x(2x - 3) = 0 \\ 2x = 0 \\ x = 0$
$2x - 3 = 0 \\ 2x = 3 \\ x = 3 \div 2 = 1.5$