Question

х в квадрате плюс 4х минус 32 равно нуль

Answer 1

х²+4х-32=0
х²+8х-4х-32=0 (8х-4х=4х)
х(х+8)-4(х+8)=0
(х+8)(х-4)=0
х+8=0
х-4=0
ответ х=-8,х=4

Answer 2

${x}^{2} + 4x - 32 = 0 \\ d = {4}^{2} - 4 \times 1 \times ( - 32) = 16 + 128 = 144 \\ x_{1} = \frac{ - 4 - \sqrt{144} }{2 \times 1} = \frac{ - 4 - 12}{2} = \frac{ - 16}{2} = - 8 \\ x_{2} = \frac{ - 4 + \sqrt{144} }{2 \times 1} = \frac{ - 4 + 12}{2} = \frac{8}{2} = 4 \\ x_{1} = - 8 \\ x_{2} = 4$