Question

помогите пожалуйста) очень нужно

Answer 1

4. 1) $\frac{2x^{2}+7 }{2x-5} = x-4$

$\frac{2x^{2}+7 }{2x-5} = x-4$,x ≠ $\frac{5}{2}$

2x²+7 = (x-4) * (2x-5)

2x² + 7 = 2x² - 5x - 8x + 20

7 = -5x - 8x + 20

7 = -13x + 20

13x = 20-7

13x=13

x = 1, x ≠ $\frac{5}{2}$

x = 1

2) $\frac{3x^{2} -8}{3x+2} = x-2$

$\frac{3x^{2} -8}{3x+2} = x-2$, x≠$-\frac{2}{3}$

3x² - 8 = (x-2) * (3x+2)

3x² - 8 = 3x² + 2x - 6x - 4

- 8 = 2x - 6x -4

-8 = -4x-4

4x = - 4 + 8

4x = 4

x = 1, x≠$-\frac{2}{3}$

x = 1