Question

Помогите срочно ю!!!

Answer 1

$\frac{(2a-2)(a-3)+(a+3)(a+3)}{(a+3)(a-3)} =5\\\frac{2a^{2}-2a-6a+6+a^{2}+3a+3a+9 }{a^{2}-9}=5\\\frac{3a^{2}-2a+15}{a^{2}-9}=5\\3a^{2}-2a+15=5(a^{2}-9)\\3a^{2}-2a+15-5a^{2}+45=0\\-2a^{2}-2a+60=0\\D=4+4*2*60=484\\a_{1}=\frac{2+\sqrt{484} }{2(-2)} =\frac{2+22}{-4}=\frac{24}{-4} =-6\\a_{2}=\frac{2-\sqrt{484} }{2(-2)}=\frac{2-22}{-4}=\frac{-20}{-4}=5$