Question

Решите неравенство
(0,5)^{-7x+12} geq 32

Answer 1

$(0,5)^{-7x+12} geq 32\\0,5=frac{5}{10}=frac{1}{2}=2^{-1},; ; 32=2^5\\2^{7x-12}geq 2^5\\7x-12geq 5\7xgeq 17\xgeq frac{17}{7},; xgeq 2frac{3}{7}$